5(p+1)(p+4)=2(7p+5)

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Solution for 5(p+1)(p+4)=2(7p+5) equation: 



5(p+1)(p+4)=2(7p+5)

We move all terms to the left:

5(p+1)(p+4)-(2(7p+5))=0

We multiply parentheses ..

5(+p^2+4p+p+4)-(2(7p+5))=0



We calculate terms in parentheses: -(2(7p+5)), so:

2(7p+5)

We multiply parentheses

14p+10

Back to the equation:

-(14p+10)



We multiply parentheses

5p^2+20p+5p-(14p+10)+20=0

We get rid of parentheses

5p^2+20p+5p-14p-10+20=0

We add all the numbers together, and all the variables

5p^2+11p+10=0

a = 5; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·5·10
Δ = -79
Delta is less than zero, so there is no solution for the equation

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