5(p-3)=3(p-2)p=

Solution for 5(p-3)=3(p-2)p= equation:

5(p-3)=3(p-2)p=

We move all terms to the left:

5(p-3)-(3(p-2)p)=0

We multiply parentheses

5p-(3(p-2)p)-15=0


We calculate terms in parentheses: -(3(p-2)p), so:

3(p-2)p

We multiply parentheses

3p^2-6p

Back to the equation:

-(3p^2-6p)


We get rid of parentheses

-3p^2+5p+6p-15=0

We add all the numbers together, and all the variables

-3p^2+11p-15=0

a = -3; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·(-3)·(-15)
Δ = -59
Delta is less than zero, so there is no solution for the equation