5(p-3)=3+(p-2)

Solution for 5(p-3)=3+(p-2) equation:

5(p-3)=3+(p-2)

We move all terms to the left:

5(p-3)-(3+(p-2))=0

We multiply parentheses

5p-(3+(p-2))-15=0


We calculate terms in parentheses: -(3+(p-2)), so:

3+(p-2)

determiningTheFunctionDomain
(p-2)+3

We get rid of parentheses

p-2+3

We add all the numbers together, and all the variables

p+1

Back to the equation:

-(p+1)


We get rid of parentheses

5p-p-1-15=0

We add all the numbers together, and all the variables

4p-16=0

We move all terms containing p to the left, all other terms to the right

4p=16

p=16/4

p=4