5(q+2)=4(q+1)

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Solution for 5(q+2)=4(q+1) equation: 



5(q+2)=4(q+1)

We move all terms to the left:

5(q+2)-(4(q+1))=0

We multiply parentheses

5q-(4(q+1))+10=0



We calculate terms in parentheses: -(4(q+1)), so:

4(q+1)

We multiply parentheses

4q+4

Back to the equation:

-(4q+4)



We get rid of parentheses

5q-4q-4+10=0

We add all the numbers together, and all the variables

q+6=0

We move all terms containing q to the left, all other terms to the right

q=-6

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