5(q-2)+q=6(q+3)-4

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Solution for 5(q-2)+q=6(q+3)-4 equation: 



5(q-2)+q=6(q+3)-4

We move all terms to the left:

5(q-2)+q-(6(q+3)-4)=0

We add all the numbers together, and all the variables

q+5(q-2)-(6(q+3)-4)=0

We multiply parentheses

q+5q-(6(q+3)-4)-10=0



We calculate terms in parentheses: -(6(q+3)-4), so:

6(q+3)-4

We multiply parentheses

6q+18-4

We add all the numbers together, and all the variables

6q+14

Back to the equation:

-(6q+14)



We add all the numbers together, and all the variables

6q-(6q+14)-10=0

We get rid of parentheses

6q-6q-14-10=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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