5(q-7)-3(2q-4)+25=0

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Solution for 5(q-7)-3(2q-4)+25=0 equation:


Simplifying
5(q + -7) + -3(2q + -4) + 25 = 0

Reorder the terms:
5(-7 + q) + -3(2q + -4) + 25 = 0
(-7 * 5 + q * 5) + -3(2q + -4) + 25 = 0
(-35 + 5q) + -3(2q + -4) + 25 = 0

Reorder the terms:
-35 + 5q + -3(-4 + 2q) + 25 = 0
-35 + 5q + (-4 * -3 + 2q * -3) + 25 = 0
-35 + 5q + (12 + -6q) + 25 = 0

Reorder the terms:
-35 + 12 + 25 + 5q + -6q = 0

Combine like terms: -35 + 12 = -23
-23 + 25 + 5q + -6q = 0

Combine like terms: -23 + 25 = 2
2 + 5q + -6q = 0

Combine like terms: 5q + -6q = -1q
2 + -1q = 0

Solving
2 + -1q = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1q = 0 + -2
-1q = 0 + -2

Combine like terms: 0 + -2 = -2
-1q = -2

Divide each side by '-1'.
q = 2

Simplifying
q = 2

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