5(r+10)=2(5r+3)+3r+4

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Solution for 5(r+10)=2(5r+3)+3r+4 equation: 



5(r+10)=2(5r+3)+3r+4

We move all terms to the left:

5(r+10)-(2(5r+3)+3r+4)=0

We multiply parentheses

5r-(2(5r+3)+3r+4)+50=0



We calculate terms in parentheses: -(2(5r+3)+3r+4), so:

2(5r+3)+3r+4

We add all the numbers together, and all the variables

3r+2(5r+3)+4

We multiply parentheses

3r+10r+6+4

We add all the numbers together, and all the variables

13r+10

Back to the equation:

-(13r+10)



We get rid of parentheses

5r-13r-10+50=0

We add all the numbers together, and all the variables

-8r+40=0

We move all terms containing r to the left, all other terms to the right

-8r=-40

r=-40/-8

r=+5

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