5(r+2)=35

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Solution for 5(r+2)=35 equation: 



5(r+2)=35

We move all terms to the left:

5(r+2)-(35)=0

We multiply parentheses

5r+10-35=0

We add all the numbers together, and all the variables

5r-25=0

We move all terms containing r to the left, all other terms to the right

5r=25

r=25/5

r=5

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