5(r+3)+9=3(r-2)+6

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Solution for 5(r+3)+9=3(r-2)+6 equation: 



5(r+3)+9=3(r-2)+6

We move all terms to the left:

5(r+3)+9-(3(r-2)+6)=0

We multiply parentheses

5r-(3(r-2)+6)+15+9=0



We calculate terms in parentheses: -(3(r-2)+6), so:

3(r-2)+6

We multiply parentheses

3r-6+6

We add all the numbers together, and all the variables

3r

Back to the equation:

-(3r)



We add all the numbers together, and all the variables

2r+24=0

We move all terms containing r to the left, all other terms to the right

2r=-24

r=-24/2

r=-12

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