5(r+3)-3(r+3)=2r+6

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Solution for 5(r+3)-3(r+3)=2r+6 equation:


Simplifying
5(r + 3) + -3(r + 3) = 2r + 6

Reorder the terms:
5(3 + r) + -3(r + 3) = 2r + 6
(3 * 5 + r * 5) + -3(r + 3) = 2r + 6
(15 + 5r) + -3(r + 3) = 2r + 6

Reorder the terms:
15 + 5r + -3(3 + r) = 2r + 6
15 + 5r + (3 * -3 + r * -3) = 2r + 6
15 + 5r + (-9 + -3r) = 2r + 6

Reorder the terms:
15 + -9 + 5r + -3r = 2r + 6

Combine like terms: 15 + -9 = 6
6 + 5r + -3r = 2r + 6

Combine like terms: 5r + -3r = 2r
6 + 2r = 2r + 6

Reorder the terms:
6 + 2r = 6 + 2r

Add '-6' to each side of the equation.
6 + -6 + 2r = 6 + -6 + 2r

Combine like terms: 6 + -6 = 0
0 + 2r = 6 + -6 + 2r
2r = 6 + -6 + 2r

Combine like terms: 6 + -6 = 0
2r = 0 + 2r
2r = 2r

Add '-2r' to each side of the equation.
2r + -2r = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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