5(r+3)-6=3(r-2)+2r

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Solution for 5(r+3)-6=3(r-2)+2r equation: 



5(r+3)-6=3(r-2)+2r

We move all terms to the left:

5(r+3)-6-(3(r-2)+2r)=0

We multiply parentheses

5r-(3(r-2)+2r)+15-6=0



We calculate terms in parentheses: -(3(r-2)+2r), so:

3(r-2)+2r

We add all the numbers together, and all the variables

2r+3(r-2)

We multiply parentheses

2r+3r-6

We add all the numbers together, and all the variables

5r-6

Back to the equation:

-(5r-6)



We add all the numbers together, and all the variables

5r-(5r-6)+9=0

We get rid of parentheses

5r-5r+6+9=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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