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5(r+3)=2(r+12)
We move all terms to the left:
5(r+3)-(2(r+12))=0
We multiply parentheses
5r-(2(r+12))+15=0
We calculate terms in parentheses: -(2(r+12)), so:We get rid of parentheses
2(r+12)
We multiply parentheses
2r+24
Back to the equation:
-(2r+24)
5r-2r-24+15=0
We add all the numbers together, and all the variables
3r-9=0
We move all terms containing r to the left, all other terms to the right
3r=9
r=9/3
r=3
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