5(r+3)=2(r-3)=53

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Solution for 5(r+3)=2(r-3)=53 equation: 



5(r+3)=2(r-3)=53

We move all terms to the left:

5(r+3)-(2(r-3))=0

We multiply parentheses

5r-(2(r-3))+15=0



We calculate terms in parentheses: -(2(r-3)), so:

2(r-3)

We multiply parentheses

2r-6

Back to the equation:

-(2r-6)



We get rid of parentheses

5r-2r+6+15=0

We add all the numbers together, and all the variables

3r+21=0

We move all terms containing r to the left, all other terms to the right

3r=-21

r=-21/3

r=-7

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