5(r+3)=2r+6.

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Solution for 5(r+3)=2r+6. equation:



5(r+3)=2r+6.
We move all terms to the left:
5(r+3)-(2r+6.)=0
We add all the numbers together, and all the variables
5(r+3)-(2r+6)=0
We multiply parentheses
5r-(2r+6)+15=0
We get rid of parentheses
5r-2r-6+15=0
We add all the numbers together, and all the variables
3r+9=0
We move all terms containing r to the left, all other terms to the right
3r=-9
r=-9/3
r=-3

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