5(r+4)=-2(r-3)=

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Solution for 5(r+4)=-2(r-3)= equation: 



5(r+4)=-2(r-3)=

We move all terms to the left:

5(r+4)-(-2(r-3))=0

We multiply parentheses

5r-(-2(r-3))+20=0



We calculate terms in parentheses: -(-2(r-3)), so:

-2(r-3)

We multiply parentheses

-2r+6

Back to the equation:

-(-2r+6)



We get rid of parentheses

5r+2r-6+20=0

We add all the numbers together, and all the variables

7r+14=0

We move all terms containing r to the left, all other terms to the right

7r=-14

r=-14/7

r=-2

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