5(r+4)=1/2(40+10r)

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Solution for 5(r+4)=1/2(40+10r) equation: 



5(r+4)=1/2(40+10r)

We move all terms to the left:

5(r+4)-(1/2(40+10r))=0



Domain of the equation: 2(40+10r))!=0

r∈R



We add all the numbers together, and all the variables

5(r+4)-(1/2(10r+40))=0

We multiply parentheses

5r-(1/2(10r+40))+20=0

We multiply all the terms by the denominator


5r*2(10r+40))-(1+20*2(10r+40))=0

Wy multiply elements

10r^2(1+40r(1=0

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