5(r+6)-3=2(2r+5)+7

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Solution for 5(r+6)-3=2(2r+5)+7 equation: 



5(r+6)-3=2(2r+5)+7

We move all terms to the left:

5(r+6)-3-(2(2r+5)+7)=0

We multiply parentheses

5r-(2(2r+5)+7)+30-3=0



We calculate terms in parentheses: -(2(2r+5)+7), so:

2(2r+5)+7

We multiply parentheses

4r+10+7

We add all the numbers together, and all the variables

4r+17

Back to the equation:

-(4r+17)



We add all the numbers together, and all the variables

5r-(4r+17)+27=0

We get rid of parentheses

5r-4r-17+27=0

We add all the numbers together, and all the variables

r+10=0

We move all terms containing r to the left, all other terms to the right

r=-10

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