5(r-)=2(r-4)-6

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Solution for 5(r-)=2(r-4)-6 equation: 



5(r-)=2(r-4)-6

We move all terms to the left:

5(r-)-(2(r-4)-6)=0

We add all the numbers together, and all the variables

5(+r)-(2(r-4)-6)=0

We multiply parentheses

5r-(2(r-4)-6)=0



We calculate terms in parentheses: -(2(r-4)-6), so:

2(r-4)-6

We multiply parentheses

2r-8-6

We add all the numbers together, and all the variables

2r-14

Back to the equation:

-(2r-14)



We get rid of parentheses

5r-2r+14=0

We add all the numbers together, and all the variables

3r+14=0

We move all terms containing r to the left, all other terms to the right

3r=-14

r=-14/3

r=-4+2/3

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