5(r-1)+2=6(r+2)-12

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Solution for 5(r-1)+2=6(r+2)-12 equation: 



5(r-1)+2=6(r+2)-12

We move all terms to the left:

5(r-1)+2-(6(r+2)-12)=0

We multiply parentheses

5r-(6(r+2)-12)-5+2=0



We calculate terms in parentheses: -(6(r+2)-12), so:

6(r+2)-12

We multiply parentheses

6r+12-12

We add all the numbers together, and all the variables

6r

Back to the equation:

-(6r)



We add all the numbers together, and all the variables

-1r-3=0

We move all terms containing r to the left, all other terms to the right

-r=3

r=3/-1

r=-3

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