5(r-1)=2(r-4)-5

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Solution for 5(r-1)=2(r-4)-5 equation: 



5(r-1)=2(r-4)-5

We move all terms to the left:

5(r-1)-(2(r-4)-5)=0

We multiply parentheses

5r-(2(r-4)-5)-5=0



We calculate terms in parentheses: -(2(r-4)-5), so:

2(r-4)-5

We multiply parentheses

2r-8-5

We add all the numbers together, and all the variables

2r-13

Back to the equation:

-(2r-13)



We get rid of parentheses

5r-2r+13-5=0

We add all the numbers together, and all the variables

3r+8=0

We move all terms containing r to the left, all other terms to the right

3r=-8

r=-8/3

r=-2+2/3

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