5(r-1)=2(r-4)-6+r/2

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Solution for 5(r-1)=2(r-4)-6+r/2 equation: 


r in (-oo:+oo)

5*(r-1) = 2*(r-4)+r/2-6 // - 2*(r-4)+r/2-6

5*(r-1)-(2*(r-4))-(r/2)+6 = 0

5*(r-1)-2*(r-4)-(r/2)+6 = 0

5*(r-1)-2*(r-4)-r/2+6 = 0

(2*5*(r-1))/2+(-2*2*(r-4))/2-r/2+(2*6)/2 = 0

2*5*(r-1)-2*2*(r-4)-r+2*6 = 0

6*r-r+6+12 = 0

5*r+6+12 = 0

5*r+18 = 0

(5*r+18)/2 = 0

(5*r+18)/2 = 0 // * 2

5*r+18 = 0

5*r+18 = 0 // - 18

5*r = -18 // : 5

r = -18/5

r = -18/5

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