5(r-2)=2(r-4)-6

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Solution for 5(r-2)=2(r-4)-6 equation: 



5(r-2)=2(r-4)-6

We move all terms to the left:

5(r-2)-(2(r-4)-6)=0

We multiply parentheses

5r-(2(r-4)-6)-10=0



We calculate terms in parentheses: -(2(r-4)-6), so:

2(r-4)-6

We multiply parentheses

2r-8-6

We add all the numbers together, and all the variables

2r-14

Back to the equation:

-(2r-14)



We get rid of parentheses

5r-2r+14-10=0

We add all the numbers together, and all the variables

3r+4=0

We move all terms containing r to the left, all other terms to the right

3r=-4

r=-4/3

r=-1+1/3

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