5(r-3)+2(r-5)=17

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Solution for 5(r-3)+2(r-5)=17 equation:


Simplifying
5(r + -3) + 2(r + -5) = 17

Reorder the terms:
5(-3 + r) + 2(r + -5) = 17
(-3 * 5 + r * 5) + 2(r + -5) = 17
(-15 + 5r) + 2(r + -5) = 17

Reorder the terms:
-15 + 5r + 2(-5 + r) = 17
-15 + 5r + (-5 * 2 + r * 2) = 17
-15 + 5r + (-10 + 2r) = 17

Reorder the terms:
-15 + -10 + 5r + 2r = 17

Combine like terms: -15 + -10 = -25
-25 + 5r + 2r = 17

Combine like terms: 5r + 2r = 7r
-25 + 7r = 17

Solving
-25 + 7r = 17

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 7r = 17 + 25

Combine like terms: -25 + 25 = 0
0 + 7r = 17 + 25
7r = 17 + 25

Combine like terms: 17 + 25 = 42
7r = 42

Divide each side by '7'.
r = 6

Simplifying
r = 6

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