5(r-3)=10(2-)

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Solution for 5(r-3)=10(2-) equation: 



5(r-3)=10(2-)

We move all terms to the left:

5(r-3)-(10(2-))=0

We add all the numbers together, and all the variables

5(r-3)-(100)=0

We add all the numbers together, and all the variables

5(r-3)-100=0

We multiply parentheses

5r-15-100=0

We add all the numbers together, and all the variables

5r-115=0

We move all terms containing r to the left, all other terms to the right

5r=115

r=115/5

r=23

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