5(r-3)=10(r/2-2)

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Solution for 5(r-3)=10(r/2-2) equation: 



5(r-3)=10(r/2-2)

We move all terms to the left:

5(r-3)-(10(r/2-2))=0

We multiply parentheses

5r-(10(r/2-2))-15=0

We multiply all the terms by the denominator


5r*2-2))-(10(r-15*2-2))=0

We add all the numbers together, and all the variables

5r*2-2))-(10(r-32))=0

We add all the numbers together, and all the variables

5r*2-2))-(10(r=0

Wy multiply elements

10r-2))-(10(r=0

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