5(r-3)=10(y/2-3)

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Solution for 5(r-3)=10(y/2-3) equation: 


x in (-oo:+oo)

5*(r-3) = 10*(y/2-3) // - 10*(y/2-3)

5*(r-3)-(10*(y/2-3)) = 0

5*(r-3)-10*(y/2-3) = 0

5*(r-3)-10*(1/2*y-3) = 0

5*(r-3)-10*(1/2*y-3) = 0

5*r-5*y+15 = 0

5*r-5*y+15 = 0

x belongs to the empty set

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