5(r-3)=2(r+6)

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Solution for 5(r-3)=2(r+6) equation: 



5(r-3)=2(r+6)

We move all terms to the left:

5(r-3)-(2(r+6))=0

We multiply parentheses

5r-(2(r+6))-15=0



We calculate terms in parentheses: -(2(r+6)), so:

2(r+6)

We multiply parentheses

2r+12

Back to the equation:

-(2r+12)



We get rid of parentheses

5r-2r-12-15=0

We add all the numbers together, and all the variables

3r-27=0

We move all terms containing r to the left, all other terms to the right

3r=27

r=27/3

r=9

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