5(r-4)-4(r-1)=2(r+3)

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Solution for 5(r-4)-4(r-1)=2(r+3) equation: 



5(r-4)-4(r-1)=2(r+3)

We move all terms to the left:

5(r-4)-4(r-1)-(2(r+3))=0

We multiply parentheses

5r-4r-(2(r+3))-20+4=0



We calculate terms in parentheses: -(2(r+3)), so:

2(r+3)

We multiply parentheses

2r+6

Back to the equation:

-(2r+6)



We add all the numbers together, and all the variables

r-(2r+6)-16=0

We get rid of parentheses

r-2r-6-16=0

We add all the numbers together, and all the variables

-1r-22=0

We move all terms containing r to the left, all other terms to the right

-r=22

r=22/-1

r=-22

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