5(r-5)-3(2-r)+35=0

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Solution for 5(r-5)-3(2-r)+35=0 equation:


Simplifying
5(r + -5) + -3(2 + -1r) + 35 = 0

Reorder the terms:
5(-5 + r) + -3(2 + -1r) + 35 = 0
(-5 * 5 + r * 5) + -3(2 + -1r) + 35 = 0
(-25 + 5r) + -3(2 + -1r) + 35 = 0
-25 + 5r + (2 * -3 + -1r * -3) + 35 = 0
-25 + 5r + (-6 + 3r) + 35 = 0

Reorder the terms:
-25 + -6 + 35 + 5r + 3r = 0

Combine like terms: -25 + -6 = -31
-31 + 35 + 5r + 3r = 0

Combine like terms: -31 + 35 = 4
4 + 5r + 3r = 0

Combine like terms: 5r + 3r = 8r
4 + 8r = 0

Solving
4 + 8r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 8r = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 8r = 0 + -4
8r = 0 + -4

Combine like terms: 0 + -4 = -4
8r = -4

Divide each side by '8'.
r = -0.5

Simplifying
r = -0.5

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