5(r-5)=-4(r-2)

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Solution for 5(r-5)=-4(r-2) equation: 



5(r-5)=-4(r-2)

We move all terms to the left:

5(r-5)-(-4(r-2))=0

We multiply parentheses

5r-(-4(r-2))-25=0



We calculate terms in parentheses: -(-4(r-2)), so:

-4(r-2)

We multiply parentheses

-4r+8

Back to the equation:

-(-4r+8)



We get rid of parentheses

5r+4r-8-25=0

We add all the numbers together, and all the variables

9r-33=0

We move all terms containing r to the left, all other terms to the right

9r=33

r=33/9

r=3+2/3

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