5(r-5)=-r+17+2r

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Solution for 5(r-5)=-r+17+2r equation: 



5(r-5)=-r+17+2r

We move all terms to the left:

5(r-5)-(-r+17+2r)=0

We add all the numbers together, and all the variables

5(r-5)-(r+17)=0

We multiply parentheses

5r-(r+17)-25=0

We get rid of parentheses

5r-r-17-25=0

We add all the numbers together, and all the variables

4r-42=0

We move all terms containing r to the left, all other terms to the right

4r=42

r=42/4

r=10+1/2

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