5(s+2)-1=3(s-4)-3

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Solution for 5(s+2)-1=3(s-4)-3 equation: 



5(s+2)-1=3(s-4)-3

We move all terms to the left:

5(s+2)-1-(3(s-4)-3)=0

We multiply parentheses

5s-(3(s-4)-3)+10-1=0



We calculate terms in parentheses: -(3(s-4)-3), so:

3(s-4)-3

We multiply parentheses

3s-12-3

We add all the numbers together, and all the variables

3s-15

Back to the equation:

-(3s-15)



We add all the numbers together, and all the variables

5s-(3s-15)+9=0

We get rid of parentheses

5s-3s+15+9=0

We add all the numbers together, and all the variables

2s+24=0

We move all terms containing s to the left, all other terms to the right

2s=-24

s=-24/2

s=-12

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