5(s+3)=3(2s+1)

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Solution for 5(s+3)=3(2s+1) equation: 



5(s+3)=3(2s+1)

We move all terms to the left:

5(s+3)-(3(2s+1))=0

We multiply parentheses

5s-(3(2s+1))+15=0



We calculate terms in parentheses: -(3(2s+1)), so:

3(2s+1)

We multiply parentheses

6s+3

Back to the equation:

-(6s+3)



We get rid of parentheses

5s-6s-3+15=0

We add all the numbers together, and all the variables

-1s+12=0

We move all terms containing s to the left, all other terms to the right

-s=-12

s=-12/-1

s=+12

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