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5(s+8)=10-(-5s-30)
We move all terms to the left:
5(s+8)-(10-(-5s-30))=0
We multiply parentheses
5s-(10-(-5s-30))+40=0
We calculate terms in parentheses: -(10-(-5s-30)), so:We get rid of parentheses
10-(-5s-30)
determiningTheFunctionDomain -(-5s-30)+10
We get rid of parentheses
5s+30+10
We add all the numbers together, and all the variables
5s+40
Back to the equation:
-(5s+40)
5s-5s-40+40=0
We add all the numbers together, and all the variables
=0
s=0/1
s=0
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