5(s+t)-(2s+4t)=

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Solution for 5(s+t)-(2s+4t)= equation:


Simplifying
5(s + t) + -1(2s + 4t) = 0
(s * 5 + t * 5) + -1(2s + 4t) = 0
(5s + 5t) + -1(2s + 4t) = 0
5s + 5t + (2s * -1 + 4t * -1) = 0
5s + 5t + (-2s + -4t) = 0

Reorder the terms:
5s + -2s + 5t + -4t = 0

Combine like terms: 5s + -2s = 3s
3s + 5t + -4t = 0

Combine like terms: 5t + -4t = 1t
3s + 1t = 0

Solving
3s + 1t = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-1t' to each side of the equation.
3s + 1t + -1t = 0 + -1t

Combine like terms: 1t + -1t = 0
3s + 0 = 0 + -1t
3s = 0 + -1t
Remove the zero:
3s = -1t

Divide each side by '3'.
s = -0.3333333333t

Simplifying
s = -0.3333333333t

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