5(sin(x))-4(cos(2x))=0

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Solution for 5(sin(x))-4(cos(2x))=0 equation:


Simplifying
5(sin(x)) + -4(cos(2x)) = 0

Multiply ins * x
5(insx) + -4(cos(2x)) = 0

Remove parenthesis around (2x)
5insx + -4(cos * 2x) = 0

Reorder the terms for easier multiplication:
5insx + -4(2cos * x) = 0

Multiply cos * x
5insx + -4(2cosx) = 0

Remove parenthesis around (2cosx)
5insx + -4 * 2cosx = 0

Multiply -4 * 2
5insx + -8cosx = 0

Reorder the terms:
-8cosx + 5insx = 0

Solving
-8cosx + 5insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5insx' to each side of the equation.
-8cosx + 5insx + -5insx = 0 + -5insx

Combine like terms: 5insx + -5insx = 0
-8cosx + 0 = 0 + -5insx
-8cosx = 0 + -5insx
Remove the zero:
-8cosx = -5insx

Divide each side by '-8osx'.
c = 0.625ino-1

Simplifying
c = 0.625ino-1

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