5(t+1)+2(9-4t)=-4(t-8)+4

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Solution for 5(t+1)+2(9-4t)=-4(t-8)+4 equation: 



5(t+1)+2(9-4t)=-4(t-8)+4

We move all terms to the left:

5(t+1)+2(9-4t)-(-4(t-8)+4)=0

We add all the numbers together, and all the variables

5(t+1)+2(-4t+9)-(-4(t-8)+4)=0

We multiply parentheses

5t-8t-(-4(t-8)+4)+5+18=0



We calculate terms in parentheses: -(-4(t-8)+4), so:

-4(t-8)+4

We multiply parentheses

-4t+32+4

We add all the numbers together, and all the variables

-4t+36

Back to the equation:

-(-4t+36)



We add all the numbers together, and all the variables

-3t-(-4t+36)+23=0

We get rid of parentheses

-3t+4t-36+23=0

We add all the numbers together, and all the variables

t-13=0

We move all terms containing t to the left, all other terms to the right

t=13

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