5(t+1)+2(9-4t)=-4(t-8)+4

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Solution for 5(t+1)+2(9-4t)=-4(t-8)+4 equation:



5(t+1)+2(9-4t)=-4(t-8)+4
We move all terms to the left:
5(t+1)+2(9-4t)-(-4(t-8)+4)=0
We add all the numbers together, and all the variables
5(t+1)+2(-4t+9)-(-4(t-8)+4)=0
We multiply parentheses
5t-8t-(-4(t-8)+4)+5+18=0
We calculate terms in parentheses: -(-4(t-8)+4), so:
-4(t-8)+4
We multiply parentheses
-4t+32+4
We add all the numbers together, and all the variables
-4t+36
Back to the equation:
-(-4t+36)
We add all the numbers together, and all the variables
-3t-(-4t+36)+23=0
We get rid of parentheses
-3t+4t-36+23=0
We add all the numbers together, and all the variables
t-13=0
We move all terms containing t to the left, all other terms to the right
t=13

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