5(t+19)+10=6(t-9)-4t

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Solution for 5(t+19)+10=6(t-9)-4t equation: 



5(t+19)+10=6(t-9)-4t

We move all terms to the left:

5(t+19)+10-(6(t-9)-4t)=0

We multiply parentheses

5t-(6(t-9)-4t)+95+10=0



We calculate terms in parentheses: -(6(t-9)-4t), so:

6(t-9)-4t

We add all the numbers together, and all the variables

-4t+6(t-9)

We multiply parentheses

-4t+6t-54

We add all the numbers together, and all the variables

2t-54

Back to the equation:

-(2t-54)



We add all the numbers together, and all the variables

5t-(2t-54)+105=0

We get rid of parentheses

5t-2t+54+105=0

We add all the numbers together, and all the variables

3t+159=0

We move all terms containing t to the left, all other terms to the right

3t=-159

t=-159/3

t=-53

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