5(t+2)-3(2t+)=-2

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Solution for 5(t+2)-3(2t+)=-2 equation: 



5(t+2)-3(2t+)=-2

We move all terms to the left:

5(t+2)-3(2t+)-(-2)=0

We add all the numbers together, and all the variables

5(t+2)-3(+2t)-(-2)=0

We add all the numbers together, and all the variables

5(t+2)-3(+2t)+2=0

We multiply parentheses

5t-6t+10+2=0

We add all the numbers together, and all the variables

-1t+12=0

We move all terms containing t to the left, all other terms to the right

-t=-12

t=-12/-1

t=+12

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