5(t+2)-3(2t+1)=2

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Solution for 5(t+2)-3(2t+1)=2 equation: 



5(t+2)-3(2t+1)=2

We move all terms to the left:

5(t+2)-3(2t+1)-(2)=0

We multiply parentheses

5t-6t+10-3-2=0

We add all the numbers together, and all the variables

-1t+5=0

We move all terms containing t to the left, all other terms to the right

-t=-5

t=-5/-1

t=+5

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