5(t+2)-3(2t-10)=-2

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Solution for 5(t+2)-3(2t-10)=-2 equation: 



5(t+2)-3(2t-10)=-2

We move all terms to the left:

5(t+2)-3(2t-10)-(-2)=0

We add all the numbers together, and all the variables

5(t+2)-3(2t-10)+2=0

We multiply parentheses

5t-6t+10+30+2=0

We add all the numbers together, and all the variables

-1t+42=0

We move all terms containing t to the left, all other terms to the right

-t=-42

t=-42/-1

t=+42

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