5(t+2)-3(t+1)=-2

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Solution for 5(t+2)-3(t+1)=-2 equation: 



5(t+2)-3(t+1)=-2

We move all terms to the left:

5(t+2)-3(t+1)-(-2)=0

We add all the numbers together, and all the variables

5(t+2)-3(t+1)+2=0

We multiply parentheses

5t-3t+10-3+2=0

We add all the numbers together, and all the variables

2t+9=0

We move all terms containing t to the left, all other terms to the right

2t=-9

t=-9/2

t=-4+1/2

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