5(t+2)=3(t-2)

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Solution for 5(t+2)=3(t-2) equation: 



5(t+2)=3(t-2)

We move all terms to the left:

5(t+2)-(3(t-2))=0

We multiply parentheses

5t-(3(t-2))+10=0



We calculate terms in parentheses: -(3(t-2)), so:

3(t-2)

We multiply parentheses

3t-6

Back to the equation:

-(3t-6)



We get rid of parentheses

5t-3t+6+10=0

We add all the numbers together, and all the variables

2t+16=0

We move all terms containing t to the left, all other terms to the right

2t=-16

t=-16/2

t=-8

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