5(t+3)+4=3(t-2)+1

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Solution for 5(t+3)+4=3(t-2)+1 equation:


Simplifying
5(t + 3) + 4 = 3(t + -2) + 1

Reorder the terms:
5(3 + t) + 4 = 3(t + -2) + 1
(3 * 5 + t * 5) + 4 = 3(t + -2) + 1
(15 + 5t) + 4 = 3(t + -2) + 1

Reorder the terms:
15 + 4 + 5t = 3(t + -2) + 1

Combine like terms: 15 + 4 = 19
19 + 5t = 3(t + -2) + 1

Reorder the terms:
19 + 5t = 3(-2 + t) + 1
19 + 5t = (-2 * 3 + t * 3) + 1
19 + 5t = (-6 + 3t) + 1

Reorder the terms:
19 + 5t = -6 + 1 + 3t

Combine like terms: -6 + 1 = -5
19 + 5t = -5 + 3t

Solving
19 + 5t = -5 + 3t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-3t' to each side of the equation.
19 + 5t + -3t = -5 + 3t + -3t

Combine like terms: 5t + -3t = 2t
19 + 2t = -5 + 3t + -3t

Combine like terms: 3t + -3t = 0
19 + 2t = -5 + 0
19 + 2t = -5

Add '-19' to each side of the equation.
19 + -19 + 2t = -5 + -19

Combine like terms: 19 + -19 = 0
0 + 2t = -5 + -19
2t = -5 + -19

Combine like terms: -5 + -19 = -24
2t = -24

Divide each side by '2'.
t = -12

Simplifying
t = -12

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