5(t+3)+4=3(t-2)+6

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Solution for 5(t+3)+4=3(t-2)+6 equation: 



5(t+3)+4=3(t-2)+6

We move all terms to the left:

5(t+3)+4-(3(t-2)+6)=0

We multiply parentheses

5t-(3(t-2)+6)+15+4=0



We calculate terms in parentheses: -(3(t-2)+6), so:

3(t-2)+6

We multiply parentheses

3t-6+6

We add all the numbers together, and all the variables

3t

Back to the equation:

-(3t)



We add all the numbers together, and all the variables

2t+19=0

We move all terms containing t to the left, all other terms to the right

2t=-19

t=-19/2

t=-9+1/2

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