5(t+3)+9=2(c-2)+3c

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Solution for 5(t+3)+9=2(c-2)+3c equation:


Simplifying
5(t + 3) + 9 = 2(c + -2) + 3c

Reorder the terms:
5(3 + t) + 9 = 2(c + -2) + 3c
(3 * 5 + t * 5) + 9 = 2(c + -2) + 3c
(15 + 5t) + 9 = 2(c + -2) + 3c

Reorder the terms:
15 + 9 + 5t = 2(c + -2) + 3c

Combine like terms: 15 + 9 = 24
24 + 5t = 2(c + -2) + 3c

Reorder the terms:
24 + 5t = 2(-2 + c) + 3c
24 + 5t = (-2 * 2 + c * 2) + 3c
24 + 5t = (-4 + 2c) + 3c

Combine like terms: 2c + 3c = 5c
24 + 5t = -4 + 5c

Solving
24 + 5t = -4 + 5c

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-24' to each side of the equation.
24 + -24 + 5t = -4 + -24 + 5c

Combine like terms: 24 + -24 = 0
0 + 5t = -4 + -24 + 5c
5t = -4 + -24 + 5c

Combine like terms: -4 + -24 = -28
5t = -28 + 5c

Divide each side by '5'.
t = -5.6 + c

Simplifying
t = -5.6 + c

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