5(t+3)+9=3(t-1)+6

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Solution for 5(t+3)+9=3(t-1)+6 equation: 



5(t+3)+9=3(t-1)+6

We move all terms to the left:

5(t+3)+9-(3(t-1)+6)=0

We multiply parentheses

5t-(3(t-1)+6)+15+9=0



We calculate terms in parentheses: -(3(t-1)+6), so:

3(t-1)+6

We multiply parentheses

3t-3+6

We add all the numbers together, and all the variables

3t+3

Back to the equation:

-(3t+3)



We add all the numbers together, and all the variables

5t-(3t+3)+24=0

We get rid of parentheses

5t-3t-3+24=0

We add all the numbers together, and all the variables

2t+21=0

We move all terms containing t to the left, all other terms to the right

2t=-21

t=-21/2

t=-10+1/2

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