5(t+3)=4(t+1)

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Solution for 5(t+3)=4(t+1) equation:


Simplifying
5(t + 3) = 4(t + 1)

Reorder the terms:
5(3 + t) = 4(t + 1)
(3 * 5 + t * 5) = 4(t + 1)
(15 + 5t) = 4(t + 1)

Reorder the terms:
15 + 5t = 4(1 + t)
15 + 5t = (1 * 4 + t * 4)
15 + 5t = (4 + 4t)

Solving
15 + 5t = 4 + 4t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-4t' to each side of the equation.
15 + 5t + -4t = 4 + 4t + -4t

Combine like terms: 5t + -4t = 1t
15 + 1t = 4 + 4t + -4t

Combine like terms: 4t + -4t = 0
15 + 1t = 4 + 0
15 + 1t = 4

Add '-15' to each side of the equation.
15 + -15 + 1t = 4 + -15

Combine like terms: 15 + -15 = 0
0 + 1t = 4 + -15
1t = 4 + -15

Combine like terms: 4 + -15 = -11
1t = -11

Divide each side by '1'.
t = -11

Simplifying
t = -11

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