5(t+4)+3(6-2t)=-2(t-6)-3

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Solution for 5(t+4)+3(6-2t)=-2(t-6)-3 equation: 



5(t+4)+3(6-2t)=-2(t-6)-3

We move all terms to the left:

5(t+4)+3(6-2t)-(-2(t-6)-3)=0

We add all the numbers together, and all the variables

5(t+4)+3(-2t+6)-(-2(t-6)-3)=0

We multiply parentheses

5t-6t-(-2(t-6)-3)+20+18=0



We calculate terms in parentheses: -(-2(t-6)-3), so:

-2(t-6)-3

We multiply parentheses

-2t+12-3

We add all the numbers together, and all the variables

-2t+9

Back to the equation:

-(-2t+9)



We add all the numbers together, and all the variables

-1t-(-2t+9)+38=0

We get rid of parentheses

-1t+2t-9+38=0

We add all the numbers together, and all the variables

t+29=0

We move all terms containing t to the left, all other terms to the right

t=-29

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