5(t+4)-4(t+1)=5

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Solution for 5(t+4)-4(t+1)=5 equation: 



5(t+4)-4(t+1)=5

We move all terms to the left:

5(t+4)-4(t+1)-(5)=0

We multiply parentheses

5t-4t+20-4-5=0

We add all the numbers together, and all the variables

t+11=0

We move all terms containing t to the left, all other terms to the right

t=-11

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